document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=926110>Question 926110</A>: <I><SPAN STYLE=\"word-break: break-all;\"> An experienced bricklayer can construct a small wall in 4 hours. An apprentice can complete the job in 6 hours. Find how long it takes if they work together. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #562000 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=562000\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x=amount of time it takes if they both work together<BR>\n" );
document.write( "Together they work at the rate of 1/x wall per hour<BR>\n" );
document.write( "Experienced bricklayer works at the rate of 1/4 wall per hour<BR>\n" );
document.write( "Apprentice works at the rate of 1/6 wall per hour<BR>\n" );
document.write( "So our equation to solve is:\r<BR>\n" );
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document.write( "1/4 + 1/6= 1/x  multiply each term by 12x<BR>\n" );
document.write( "3x+2x=12<BR>\n" );
document.write( "5x=12<BR>\n" );
document.write( "x=2.4 hours---time it takes if they both work together\r<BR>\n" );
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document.write( "Check<BR>\n" );
document.write( "In 2.4 hours, experienced bricklayer lays (1/4)*2.4=0.6 of a wall<BR>\n" );
document.write( "In 2.4 hours apprentice lays (1/6)*2.4=0.4 of a wall<BR>\n" );
document.write( "0.6+0.4=1 (wall, that is)\r<BR>\n" );
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document.write( "Hope this helps--ptaylor<BR>\n" );
document.write( " </SPAN>\n" );
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