document.write( "Question 78377: I am not sure if this is solved by substitution, or elimination\r
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document.write( "4x - 6y = -14
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document.write( "x + 4y = 13 \n" );
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Algebra.Com's Answer #56200 by dolly(163)![]() ![]() ![]() You can put this solution on YOUR website! Solution by substitution:\r \n" ); document.write( "\n" ); document.write( "x + 4y = 13 \n" ); document.write( "==> x = 13 -4y ------------------(i) \n" ); document.write( "Plugging in this value of x in the first equation, we get, \n" ); document.write( "4(13-4y) - 6y = -14 \n" ); document.write( "==> 52 - 16y - 6y = -14 \n" ); document.write( "==> 52 - 22y = -14 \n" ); document.write( "adding -52 to both sides, \n" ); document.write( "-22y = -14 -52 \n" ); document.write( "==> -22y = -66 \n" ); document.write( "==> -22y/22 = -66/22 \n" ); document.write( "==> y = 3 \n" ); document.write( "Putting this value in (i), x = 13 -4(3) \n" ); document.write( " = 13 - 12 \n" ); document.write( " = 1\r \n" ); document.write( "\n" ); document.write( "Thus x = 1 and y = 3\r \n" ); document.write( "\n" ); document.write( "Solution by elimination:\r \n" ); document.write( "\n" ); document.write( "4x - 6y = -14----------------------(1) \n" ); document.write( "x + 4y = 13 ----------------------(2)\r \n" ); document.write( "\n" ); document.write( "==> 4x + 16y = 52 -----------(2) x 4 \n" ); document.write( " 4x - 6y = - 14 -------------(1) \n" ); document.write( "Subtracting the two equations we get,\r \n" ); document.write( "\n" ); document.write( "16y + 6y = 52 + 14 \n" ); document.write( "==> 22y = 66 \n" ); document.write( "==> 22y/22= 66/22 \n" ); document.write( "==> y = 3 \n" ); document.write( "Plugging in this in (2), x = 13 - 4y\r \n" ); document.write( "\n" ); document.write( " = 13 - 4(3) \n" ); document.write( " = 13 - 12 \n" ); document.write( " = 1\r \n" ); document.write( "\n" ); document.write( "Thus x = 1, y = 3 \n" ); document.write( " \n" ); document.write( " |