document.write( "Question 925977: Please help me solve this equation:\r
\n" ); document.write( "\n" ); document.write( "if the latus rectum of an ellipse is 5 and eccentricity is 2/3, find the value of a and b ?
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Algebra.Com's Answer #561901 by srinivas.g(540)\"\" \"About 
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latus rectum of an ellipse =\"+2b%5E2%2Fa\"
\n" ); document.write( " eccentricity = \"+sqrt%281-b%5E2%2Fa%5E2%29\"
\n" ); document.write( "\"+2b%5E2%2Fa++=5\"
\n" ); document.write( " move a to the right
\n" ); document.write( " 2b^2 = 5a
\n" ); document.write( " divide with 2 on both sides
\n" ); document.write( " \"+2b%5E2%2F2+=++5a%2F2\"
\n" ); document.write( " \"+b%5E2+=5a%2F2\"
\n" ); document.write( "put above in eccentricity equation
\n" ); document.write( "
\n" ); document.write( " eccentricity = \"+sqrt%281-b%5E2%2Fa%5E2%29\"
\n" ); document.write( " \"2%2F3+=+sqrt%281-b%5E2%2Fa%5E2%29\"
\n" ); document.write( " \"2%2F3+=sqrt%281-%285a%2F2%29%2Fa%5E2%29\"
\n" ); document.write( " \"2%2F3+=sqrt%281-5%2F2a%29\" \r
\n" ); document.write( "\n" ); document.write( "squaring on both sides
\n" ); document.write( " \"+%282%2F3%29%5E2++=%28sqrt%281-5%2F2a%29%29%5E2\"
\n" ); document.write( " \"+4%2F9=1-5%2F2a\"
\n" ); document.write( " move 1 to the left
\n" ); document.write( " \"4%2F9-1+=-5%2F2a\"
\n" ); document.write( " \"+4%2F9+-9%2F9+=-5%2F2a\"
\n" ); document.write( " \"+%284-9%29%2F9+=-5%2F2a\"
\n" ); document.write( " \"-5%2F9+=-5%2F2a\"
\n" ); document.write( " \"5%2F9+=5%2F2a\"
\n" ); document.write( " divide with 5 on both sides
\n" ); document.write( " \"+5%2F9+%2A1%2F5+=+5%2F2a%2A1%2F5\"
\n" ); document.write( " \"+1%2F9+=+1%2F2a\"
\n" ); document.write( " 2a =9
\n" ); document.write( " on dividing with 2 on both sides
\n" ); document.write( " a = 9/2
\n" ); document.write( "but \"+b%5E2++=+5%2Aa%2F2\"
\n" ); document.write( " =\"5%2A+%289%2F2%29%2F2\"
\n" ); document.write( " =\"45%2F4\"
\n" ); document.write( " \"++b+=+sqrt%2845%2F4%29\"
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