document.write( "Question 925983: In how many ways can 4 large books, 3 medium- size books, and 2 small books, be placed on a shelf so that all books of the same size are together \n" ); document.write( "
Algebra.Com's Answer #561896 by srinivas.g(540)![]() ![]() You can put this solution on YOUR website! let as assume 4 large books as 1 unit and 3 medium- size book as another unit and 2 small books as one more unit \n" ); document.write( "these 3 units can be arranged in 3! ways \n" ); document.write( "first unit consist of 4 large books. these books can be internally arranged in 4! ways \n" ); document.write( "second unit consist of 3 medium sized books. these books can be internally arranged in 3! ways \n" ); document.write( "third unit consist of 2 small books. these books can be internally arranged in 2! ways\r \n" ); document.write( "\n" ); document.write( "Total no of ways = 3! * 4!*3!*2! \n" ); document.write( "3 ! = 3x2x1 = 6 \n" ); document.write( "4!~=4x3x2x1 = 24 \n" ); document.write( "2! = 2x1 =2 \n" ); document.write( " result = 3! * 4!*3!*2! \n" ); document.write( " = 6*24*6*2 \n" ); document.write( " =1728 \n" ); document.write( " |