document.write( "Question 925982: the width of a rectangle is 6 feet less than twice its length. If its area is 108 square feet, find the dimensions of the rectangle \n" ); document.write( "

Algebra.Com's Answer #561891 by srinivas.g(540) $\"\"$ $\"About$

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let length of rectangle be l
\n" ); document.write( "width = 2*length -6
\n" ); document.write( " width =2l-6
\n" ); document.write( "Area of rectangle = 108 square feet
\n" ); document.write( " Area = length* width
\n" ); document.write( " 108 = l*(2l-6)
\n" ); document.write( "108 = l*(2l)+l*(-6)
\n" ); document.write( " $\"108=+2l%5E2-6l\"$
\n" ); document.write( " move 108 to the right
\n" ); document.write( " $\"+2l%5E2-6l-108=0\"$
\n" ); document.write( " divide each term with 2
\n" ); document.write( " $\"+2l%5E2%2F2+-6l%2F2-108%2F2+=+0\"$
\n" ); document.write( " $\"+l%5E2-3l-54=0\"$
\n" ); document.write( " $\"+l%5E2-9l%2B6l-54=0\"$
\n" ); document.write( " $\"+l%28l-9%29%2B6%28l-9%29=0\"$
\n" ); document.write( " $\"+%28l-9%29%28l%2B6%29=0\"$
\n" ); document.write( "from above equation , the possibilities are
\n" ); document.write( " l-9= 0 or l+6 = 0
\n" ); document.write( " l=9 or l=-6
\n" ); document.write( "since l is length , it cannot be negative
\n" ); document.write( "hence l is 9 foot
\n" ); document.write( " width = 2*length -6
\n" ); document.write( " = 2*9-6
\n" ); document.write( " =18-6
\n" ); document.write( " =12
\n" ); document.write( "width = 12 feet
\n" ); document.write( "length = 9 feet \n" ); document.write( "

\n" );