document.write( "Question 925866: Pipe A can fill a tank in 25 minutes. Pipe B can fill the same tank in 20 minutes. To fill the empty tank, pipe A was opened alone for 3 minutes, and, after that, pipe B was also opened. How much time will it take for both pipes, A and B to finish filling the tank? \n" ); document.write( "
Algebra.Com's Answer #561840 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
Pipe A can fill a tank in 25 minutes.
\n" ); document.write( " Pipe B can fill the same tank in 20 minutes.
\n" ); document.write( " To fill the empty tank, pipe A was opened alone for 3 minutes, and, after that, pipe B was also opened.
\n" ); document.write( " How much time will it take for both pipes, A and B to finish filling the tank?
\n" ); document.write( ":
\n" ); document.write( "let t = for A & B to finish filling the tank
\n" ); document.write( "let the completed job = 1 (a full tank)
\n" ); document.write( ":
\n" ); document.write( "A shared work equation
\n" ); document.write( "\"%28%28t%2B3%29%29%2F25\" + \"t%2F20\" - 1
\n" ); document.write( "multiply equation by 100, cancel the denominators
\n" ); document.write( "4(t+3) + 5t = 100
\n" ); document.write( "4t + 12 + 5t = 100
\n" ); document.write( "4t + 5t = 100 - 12
\n" ); document.write( "9t = 88
\n" ); document.write( "t = 9.78 minutes for A & B to finish filling the tank
\n" ); document.write( "
\n" ); document.write( "
\n" );