document.write( "Question 925851: 2 * 3^2x = 5 (The exponent on 3 is 2x.)\r
\n" ); document.write( "\n" ); document.write( "I have the answer for this question but I do not understand how to do it. Could you please provide me with the steps with an explanation. Thanks!
\n" ); document.write( "

Algebra.Com's Answer #561818 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
\"2+%2A+3%5E%282x%29+=+5+\"
\n" ); document.write( "divide both sides by 2
\n" ); document.write( "\"3%5E%282x%29+=+2.5+\"
\n" ); document.write( "use logs here
\n" ); document.write( "\"log%28%283%5E%282x%29%29%29+=+log%28%282.5%29%29+\"
\n" ); document.write( "the log equiv of exponents
\n" ); document.write( "2x*log(3) = log(2.5)
\n" ); document.write( "2x = \"log%28%282.5%29%29%2Flog%28%283%29%29\"
\n" ); document.write( "using a calc we have
\n" ); document.write( "2x = .834
\n" ); document.write( "x = .834/2
\n" ); document.write( "x = .417
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "confirm this on your calc enter 2 * 3^(2*.417)\r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );