document.write( "Question 925847: log(5x) = log3+log(x-2) ...Just like that; no bases. PLEASE HELP!! -If you can go step by step with explanations that would be sooo helpful. Thank you!! \n" ); document.write( "
Algebra.Com's Answer #561807 by lwsshak3(11628)\"\" \"About 
You can put this solution on YOUR website!
log(5x) = log3+log(x-2)
\n" ); document.write( "when no base is shown, the base=10.
\n" ); document.write( "\"log%285x%29-log%28x-2%29=log%283%29\"
\n" ); document.write( "\"log%28%285x%2F%28x-2%29%29%29=log%28%283%29%29\"
\n" ); document.write( "\"5x%2F%28x-2%29=3\"
\n" ); document.write( "5x=3x-6
\n" ); document.write( "2x=-6
\n" ); document.write( "x=-3
\n" ); document.write( "no solution: x>0
\n" ); document.write( "
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