document.write( "Question 925703: A local television station wants to estimate the average number of hours people spend watching television each day. They randomly sample 400 individuals in their viewing area and find that, on average, people watch 3.5 hours of television a day. It is known, however, that the population standard deviation is 2.0 hours. \r
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document.write( "a - determine the standard error of the mean. \r
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document.write( "b - compute a 99% confidence interval for the mean number of hours spent watching television. \r
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document.write( "c - interpret the result of the confidence interval in a sentence or two \n" );
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Algebra.Com's Answer #561689 by ewatrrr(24785)![]() ![]() You can put this solution on YOUR website! Sample mean = 2.4, SD = 2 \n" ); document.write( "SE = 2/sqrt(400) \n" ); document.write( "ME = 2.576 (.1) = .2576 \n" ); document.write( "CI: 2.4 - .26 < u < 2.4 + .26 \n" ); document.write( "CI: (2.14, 2.66) \n" ); document.write( "CI: (2.1, 2.7) \n" ); document.write( "Use the Number of Decimals Points as Directed for Class Use. \n" ); document.write( " |