document.write( "Question 78327This question is from textbook Algebra Structure and Method Book 1
\n" ); document.write( ": Find the length of a side of a square whose area is the same as that of a rectangle 24 cm. by 30 cm. \n" ); document.write( "
Algebra.Com's Answer #56168 by jim_thompson5910(35256)\"\" \"About 
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Since the areas are equal we can find the area of the rectangle to find the area of the square:\r
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\n" ); document.write( "\n" ); document.write( "Area of rectangle=base*height=24*30=720\r
\n" ); document.write( "\n" ); document.write( "So the area of the rectangle is 720 square centimeters. Now we know the area of the square is 720 square centimeters also. Now we have this relationship:\r
\n" ); document.write( "\n" ); document.write( "Area of square=side*side=(side)^2\r
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\n" ); document.write( "\n" ); document.write( "Let s=side\r
\n" ); document.write( "\n" ); document.write( "So we have\r
\n" ); document.write( "\n" ); document.write( "Area of square\r
\n" ); document.write( "\n" ); document.write( "\"A=s%5E2\"\r
\n" ); document.write( "\n" ); document.write( "\"720=s%5E2\" Plug in A=720 and solve for s\r
\n" ); document.write( "\n" ); document.write( "\"sqrt%28720%29=sqrt%28s%5E2%29\" take the square root of both sides\r
\n" ); document.write( "\n" ); document.write( "\"s=sqrt%28720%29\"\r
\n" ); document.write( "\n" ); document.write( "Now reduce:\r
\n" ); document.write( "\n" ); document.write( "\"s=sqrt%28144%2A5%29\"\r
\n" ); document.write( "\n" ); document.write( "\"s=sqrt%28144%29%2Asqrt%285%29\"\r
\n" ); document.write( "\n" ); document.write( "\"s=12%2Asqrt%285%29\"\r
\n" ); document.write( "\n" ); document.write( "So the side of the square is about 26.83 cm long
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