document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=925595>Question 925595</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me on my homework on age problem on linear equation in one variable:....\"Six years ago Carl was three times as old as John.Eight years hence,four times Carl's age will be five times John's age.Find their present ages.\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #561667 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=561667\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let x be Carl's age and y be John's age, then<BR>\n" );
document.write( "(x-6) = 3*(y-6)<BR>\n" );
document.write( "4*(x+8) = 5*(y+8)<BR>\n" );
document.write( "first equation becomes<BR>\n" );
document.write( "x-6 = 3y-18<BR>\n" );
document.write( "x - 3y = -12<BR>\n" );
document.write( "x = 3y -12<BR>\n" );
document.write( "substitute for x in second equation<BR>\n" );
document.write( "4*(3y-12+8) = 5y+40<BR>\n" );
document.write( "12y-16 = 5y+40<BR>\n" );
document.write( "7y = 56<BR>\n" );
document.write( "y = 8, then use first equation<BR>\n" );
document.write( "x-6 = 3*(8-6)<BR>\n" );
document.write( "x-6 = 6<BR>\n" );
document.write( "x = 12<BR>\n" );
document.write( "therefore<BR>\n" );
document.write( "Carl is 12 and John is 8<BR>\n" );
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