document.write( "Question 925611: Please Help!!! Q)Four friends A,B,C and D together fave 120 marbles. The number of marbles with A is 1/4 the total number of marbles with the other three. Marbles with B is 1/3 of the total marbles with the other three. C has 3/7 of the marbles with others. Who among A,B,C and D has the most of marbles? \n" ); document.write( "
Algebra.Com's Answer #561659 by rothauserc(4718)![]() ![]() You can put this solution on YOUR website! We are given 4 equations, \n" ); document.write( "A +B +C +D = 120 \n" ); document.write( "A = (1/4) * (B+C+D) \n" ); document.write( "B = (1/3) * (A+C+D) \n" ); document.write( "C = 120 - (A+B+C) \n" ); document.write( "from the second equation, we have \n" ); document.write( "4A = (B+C+D) \n" ); document.write( "substitute in first equation, \n" ); document.write( "A +4A = 120 \n" ); document.write( "5A = 120 \n" ); document.write( "A = 24 \n" ); document.write( "from the third equation, we have \n" ); document.write( "3B = (A+C+D) \n" ); document.write( "substitute in first equation \n" ); document.write( "B +3B = 120 \n" ); document.write( "4B = 120 \n" ); document.write( "B = 30 \n" ); document.write( "from fourth equation, we have \n" ); document.write( "C = 120 - (54+D) \n" ); document.write( "C = 66 -D \n" ); document.write( "C+D = 66 \n" ); document.write( "C =54 \n" ); document.write( "to find D, we have \n" ); document.write( "24 +30 +54 +D = 120 \n" ); document.write( "108 +D = 120 \n" ); document.write( "D = 12 \n" ); document.write( "therefore, \n" ); document.write( "A has 24 marbles, B has 30 marbles, C has 54 marbles, D has 12 marbles \n" ); document.write( "C has the most marbles which is 54\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |