document.write( "Question 925558: Graph the equation
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document.write( "6y-12=0 \n" );
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Algebra.Com's Answer #561624 by Edwin McCravy(20054)![]() ![]() You can put this solution on YOUR website! \r\n" ); document.write( "6y-12=0\r\n" ); document.write( "\r\n" ); document.write( "When you have an equation of a line with only one letter in it\r\n" ); document.write( "like this, one way to graph it is to add 0 times the missing \r\n" ); document.write( "letter to it. In this case x is missing, so add 0x to the \r\n" ); document.write( "equation. That is, make it:\r\n" ); document.write( "\r\n" ); document.write( "0x+6y-12=0\r\n" ); document.write( "\r\n" ); document.write( "Now make a table of values, substituting different arbitrary values\r\n" ); document.write( "for the missing letter:\r\n" ); document.write( "\r\n" ); document.write( " x | y\r\n" ); document.write( " -----\r\n" ); document.write( " 0 |\r\n" ); document.write( " 1 |\r\n" ); document.write( "-3 |\r\n" ); document.write( " 5 |\r\n" ); document.write( "\r\n" ); document.write( "Substitute x=0: Substitute x=1: Substitute x=-3 Substitute x=5 \r\n" ); document.write( "\r\n" ); document.write( " 0x+6y-12=0 0x+6y-12=0 0x+6y-12=0 0x+6y-12=0\r\n" ); document.write( "0(0)+6y-12=0 0(1)+6y-12=0 0(-3)+6y-12=0 0(5)+6y-12=0\r\n" ); document.write( " 0+6y-12=0 0+6y-12=0 0+6y-12=0 0+6y-12=0\r\n" ); document.write( " 6y-12=0 6y-12=0 6y-12=0 6y-12=0\r\n" ); document.write( " 6y=12 6y=12 6y=12 6y=12\r\n" ); document.write( " y=2 y=2 y=2 y=2\r\n" ); document.write( "\r\n" ); document.write( "Now we have filled in the table:\r\n" ); document.write( "\r\n" ); document.write( " x | y\r\n" ); document.write( " -----\r\n" ); document.write( " 0 | 2\r\n" ); document.write( " 1 | 2\r\n" ); document.write( "-3 | 2\r\n" ); document.write( " 5 | 2\r\n" ); document.write( "\r\n" ); document.write( "So we plot the points (0,2), (1,2), (-3,2), and (5,2)\r\n" ); document.write( "\r\n" ); document.write( "\n" ); document.write( " |