document.write( "Question 925566: Insert 4 geometric means between 1/8 and 64.\r
\n" );
document.write( "\n" );
document.write( "I've worked on this so far:\r
\n" );
document.write( "\n" );
document.write( "an = a₁r^n – 1
\n" );
document.write( "a₁ = 1/8, a₆ = 64
\n" );
document.write( "64 = (1/8)r⁶⁻'
\n" );
document.write( "r⁵ = 512
\n" );
document.write( "r = 4\r
\n" );
document.write( "\n" );
document.write( "an = a₁r^n – 1
\n" );
document.write( "an = (1/8)(4)4^n – 1\r
\n" );
document.write( "\n" );
document.write( "and I don't know if I'm wrong or not, so please let me know if I am. \n" );
document.write( "
Algebra.Com's Answer #561601 by srinivas.g(540)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( " a1 = 1/8 \n" ); document.write( "a6=64 \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " move 8 to th right \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " here \"r\" is not equals to 4 \n" ); document.write( " \n" ); document.write( " r= 3.48 \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " = \n" ); document.write( " =1.5138 \n" ); document.write( " \n" ); document.write( " = \n" ); document.write( " =5.26 \n" ); document.write( " \n" ); document.write( " =18.33 \n" ); document.write( "so four geometric means = 0.435 , 1.5138,5.26,18.33\r \n" ); document.write( "\n" ); document.write( "Remarks: As per my observation , r may not be 3.48. I hope there is mistake in the problem. it should be 1/16 instead of 1/8 \n" ); document.write( " then r = 4 \n" ); document.write( " a2 = 1/4 \n" ); document.write( " a3 = 1 \n" ); document.write( " a4 = 4 \n" ); document.write( " a5 =16 \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |