document.write( "Question 925562: How would I solve the dimensions of a rectangle if the length is 3cm more than the width and the diagonal is 15cm?\r
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document.write( "I'm supposed to use factored form for the problem but I haven't been able to solve it. I know it has something to do with isolating w. \r
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document.write( "So far, I've subbed in w + 3 for the length and tried pythagorean theorem. But that answers keep coming up wrong. They should be 12 by 9. \n" );
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Algebra.Com's Answer #561598 by srinivas.g(540)![]() ![]() You can put this solution on YOUR website! Let width be w cm \n" ); document.write( "length = (w+3) cm \n" ); document.write( "diagonal = 15 cm \n" ); document.write( "as per pythagorean theorem \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " move 225 to the right \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " on dividing with 2 both sides \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " (w-9) =0 or (w+12 )= 0 \n" ); document.write( " w=9 or w=-12 \n" ); document.write( " w cannot be negative \n" ); document.write( "so w= 9 \n" ); document.write( " l = w+3 = 12 \n" ); document.write( "so length = 12 cm \n" ); document.write( " width = 9 cm\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |