document.write( "Question 925522: A canoe going 6 miles upstream in the same time that it takes to travel 10 miles downstream. The current is
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Algebra.Com's Answer #561567 by stanbon(75887)\"\" \"About 
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A canoe going 6 miles upstream in the same time that it takes to travel 10 miles downstream. The current is flowing at 1 mph.
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\n" ); document.write( "Upstream DATA::
\n" ); document.write( "distance = 6 miles ; rate = c-1 mph ; time = d/r = 6/(c-1) hrs
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\n" ); document.write( "Downstream DATA:
\n" ); document.write( "distance = 10 miles ; rate = c+1 mph ; time = d/r = 10/(c+1) hrs
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\n" ); document.write( "Equation:
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\n" ); document.write( "6/(c-1) = 10/(c+1)
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\n" ); document.write( "6c+6 = 10c - 10
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\n" ); document.write( "4c = 16
\n" ); document.write( "c = 4 mph (speed of the canoe in still water)
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\n" ); document.write( "Cheers,
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