document.write( "Question 78305This question is from textbook
\n" ); document.write( ": The line through (0, -1) that is perpendicular to 2x - 5y = 10 \n" ); document.write( "
Algebra.Com's Answer #56155 by ankor@dixie-net.com(22740)\"\" \"About 
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The line through (0, -1) that is perpendicular to 2x - 5y = 10
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\n" ); document.write( "First find the slope by putting 2x - 5y = 10 in the slope/intercept form:
\n" ); document.write( "y = mx + b is the form we want
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\n" ); document.write( "2x - 5y = 10
\n" ); document.write( "-5y = -2x + 10
\n" ); document.write( "5y = 2x - 10; multiplied by -1 to make y positive
\n" ); document.write( "y = (2/5)x - 10/5; divided both sides by 5
\n" ); document.write( "y = (2/5)x - 2,
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\n" ); document.write( "The slope is 2/5; let m1 = 2/5
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\n" ); document.write( "The relationship of the slopes of perpendicular lines are: m1*m2 = -1
\n" ); document.write( "Find m2:
\n" ); document.write( "(2/5)*m2 = -1
\n" ); document.write( "m2 = -5/2 is the slope of the perpendicular line.
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\n" ); document.write( "Find the perpendicular line using the point/slope equation; y - y1 = m(x - x1)
\n" ); document.write( "Given that x1 = 0, y1 =-1; and we found m2 = -5/2
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\n" ); document.write( "y - (-1) = (-5/2)(x - 0)
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\n" ); document.write( "y + 1 = -(5/2)x
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\n" ); document.write( "y = -(5/2)x - 1; Subtract 1 from both sides, this is the perpendicular line
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