document.write( "Question 925454: There are 15 animals in the field. Some are sheep and some are chickens. There are 40 legs in all. How many of each animal are in the field?
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Algebra.Com's Answer #561546 by jim_thompson5910(35256) $\"\"$ $\"About$

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Hints:\r
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\n" ); document.write( "\n" ); document.write( "x = number of sheep
\n" ); document.write( "y = number of chickens\r
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\n" ); document.write( "\n" ); document.write( "15 animals total: x+y = 15
\n" ); document.write( "40 legs in all: 4x+2y = 40\r
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\n" ); document.write( "\n" ); document.write( "So you need to solve this system\r
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\n" ); document.write( "\n" ); document.write( " $\"system%28x%2By+=+15%2C4x%2B2y+=+40%29\"$ \r
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\n" ); document.write( "\n" ); document.write( "it might help to solve equation 1 for y to get $\"y+=+15-x\"$ and then plug that into equation 2 to get $\"4x%2B2%2815-x%29=40\"$ . Solve for x and then use that to find y. \n" ); document.write( "

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