document.write( "Question 925262: Distance rate time problem I think. Tried making that chart thing but don't know what to put where in it and can't figure it out. \r
\n" ); document.write( "\n" ); document.write( "Hank goes 10 mph in still water. He notices one day he goes 4 miles upstream in the same amount of time he goes downstream. What is the approximate speed of that day?
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Algebra.Com's Answer #561392 by stanbon(75887)\"\" \"About 
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Hank goes 10 mph in still water. He notices one day he goes 4 miles upstream in the same amount of time he goes downstream. What is the approximate speed of that day?
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\n" ); document.write( "Upstream DATA:
\n" ); document.write( "distance = 4 miles ; rate = 10-c ; time = d/r = 4/(10-c) hrs
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\n" ); document.write( "Downstream DATA:
\n" ); document.write( "distance = 4 miles ; rate = 10+c ; time = d/r = 4/(10+c) hrs
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\n" ); document.write( "Equation:
\n" ); document.write( "4/(10-c) = 4/(10+c)
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\n" ); document.write( "Comment:: Either the speed of the current is zero or
\n" ); document.write( "his distance downstream is different then his distance
\n" ); document.write( "upstream. Please check your problem statement.
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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