document.write( "Question 925258: A ball with a 22-in. circumference is tightly packed into a cubical box for shipment. (Round your answers to the nearest whole number.)
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document.write( "(a) What is the volume of the ball?
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document.write( "(b) What is the smallest possible volume for the box?
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document.write( "(c) What percent of the space in the box is occupied by the ball?
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Algebra.Com's Answer #561381 by stanbon(75887) ![]() You can put this solution on YOUR website! A ball with a 22-in. circumference is tightly packed into a cubical box for shipment. (Round your answers to the nearest whole number.) \n" ); document.write( "--- \n" ); document.write( "Find the diameter of the ball:: \n" ); document.write( "pi*d = 22 \n" ); document.write( "diameter = 22/pi inches \n" ); document.write( "----------------------------- \n" ); document.write( " (a) What is the volume of the ball in cubic inches? \n" ); document.write( "V = (4/3)pi*r^3 = (4/3)pi*(11/pi)^3 = (1774.67)/pi^2 in^3 \n" ); document.write( "---------------------------------------------------------- \n" ); document.write( "(b) What is the smallest possible volume for the box? in3 \n" ); document.write( "V = s^3 = (22/pi)^3 = 10648/pi^3 in^3 \n" ); document.write( "-------------------------------------------- \n" ); document.write( "(c) What percent of the space in the box is occupied by the ball? \n" ); document.write( " [(4/3)pi*(11/pi)^3 / (22/pi)^3 = [(4/3)*11^3/p^2]/(22/pi)^3) \n" ); document.write( "= [(4/3)*11^3*pi/22^3] = 52.36% \n" ); document.write( "---------------------------------- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "----------------- \n" ); document.write( " |