document.write( "Question 925250: A and B do a job in 12 days . A did for 8 days then rest job was done by B in 20 days. Find individually A and B can do in how many days. \n" ); document.write( "
Algebra.Com's Answer #561375 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! A and B do a job in 12 days . A did for 8 days then rest job was done by B in 20 days. Find individually A and B can do in how many days. \n" ); document.write( "--- \n" ); document.write( "Together rate:: 1/12 job/day \n" ); document.write( "A's rate:: 1/a job/day \n" ); document.write( "B's rate:: 1/b job/day \n" ); document.write( "----- \n" ); document.write( "Equations: \n" ); document.write( "1/a + 1/b = 1/12 \n" ); document.write( "3(1/a) + 20(1/b) = 1 \n" ); document.write( "---------- \n" ); document.write( "Modify:: \n" ); document.write( "12b + 12a = ab \n" ); document.write( "3b + 20a = ab \n" ); document.write( "----- \n" ); document.write( "Modify for elimination:: \n" ); document.write( "12b + 12a = ab \n" ); document.write( "12b + 80a = 4ab \n" ); document.write( "---- \n" ); document.write( "Subtract:: \n" ); document.write( "68a = 2ab \n" ); document.write( "b = 34 days (time for B to do the job alone) \n" ); document.write( "--- \n" ); document.write( "Solve for \"a\": \n" ); document.write( "1/a + 1/34 = 1/12 \n" ); document.write( "1/a = 1/12 - 1/34 \n" ); document.write( "1/a = (34-12)/(12*34) \n" ); document.write( "1/a = 22/(12*34) \n" ); document.write( "a = (12*34)/22 \n" ); document.write( "a = 8.55 days (time for A to do the job alone) \n" ); document.write( "---------------------- \n" ); document.write( " |