document.write( "Question 925250: A and B do a job in 12 days . A did for 8 days then rest job was done by B in 20 days. Find individually A and B can do in how many days. \n" ); document.write( "
Algebra.Com's Answer #561375 by stanbon(75887)\"\" \"About 
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A and B do a job in 12 days . A did for 8 days then rest job was done by B in 20 days. Find individually A and B can do in how many days.
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\n" ); document.write( "Together rate:: 1/12 job/day
\n" ); document.write( "A's rate:: 1/a job/day
\n" ); document.write( "B's rate:: 1/b job/day
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\n" ); document.write( "Equations:
\n" ); document.write( "1/a + 1/b = 1/12
\n" ); document.write( "3(1/a) + 20(1/b) = 1
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\n" ); document.write( "Modify::
\n" ); document.write( "12b + 12a = ab
\n" ); document.write( "3b + 20a = ab
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\n" ); document.write( "Modify for elimination::
\n" ); document.write( "12b + 12a = ab
\n" ); document.write( "12b + 80a = 4ab
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\n" ); document.write( "Subtract::
\n" ); document.write( "68a = 2ab
\n" ); document.write( "b = 34 days (time for B to do the job alone)
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\n" ); document.write( "Solve for \"a\":
\n" ); document.write( "1/a + 1/34 = 1/12
\n" ); document.write( "1/a = 1/12 - 1/34
\n" ); document.write( "1/a = (34-12)/(12*34)
\n" ); document.write( "1/a = 22/(12*34)
\n" ); document.write( "a = (12*34)/22
\n" ); document.write( "a = 8.55 days (time for A to do the job alone)
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