document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=924662>Question 924662</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the unknown quantity in the given equation. <BR>\n" );
document.write( "log1/2 (3 - x) = -3 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #561334 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=561334\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Find the unknown quantity in the given equation.<BR>\n" );
document.write( "log1/2 (3 - x) = -3<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=log%281%2F2%2C%283-x%29%29=-3 ALIGN=MIDDLE  ALT=\"log%281%2F2%2C%283-x%29%29=-3\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "base(1/2) raised to log of number(-3)=number(3-x)<BR>\n" );
document.write( "(1/2)^-3=3-x<BR>\n" );
document.write( "8=3-x<BR>\n" );
document.write( "x=-5\r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
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