document.write( "Question 924647: log2(x)+log2(x-4)=log2(x+24)
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Algebra.Com's Answer #561331 by lwsshak3(11628) $\"\"$ $\"About$

You can put this solution on YOUR website!
log2(x)+log2(x-4)=log2(x+24)
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\n" ); document.write( " $\"log%282%2C%28x%29%29%2Blog%282%2C%28x-4%29%29=log%282%2C%28x%2B24%29%29%29\"$
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\n" ); document.write( "base(2) raised to log of number(0)=number(x)(x-4)/(x+24))
\n" ); document.write( "2^0=(x)(x-4)/(x+24))
\n" ); document.write( "(x^2-4x)/(x+24)=1
\n" ); document.write( "(x^2-4x)=(x+24)
\n" ); document.write( "x^2-5x-24=0
\n" ); document.write( "(x-8)(x+3)=0
\n" ); document.write( "x=-3 (reject)
\n" ); document.write( "x=8 \n" ); document.write( "

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