document.write( "Question 925116: solve graphically:
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Algebra.Com's Answer #561325 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!
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Solved by pluggable solver: Graphing Linear Equations
In order to graph \"y=1%2Ax-2\" we only need to plug in two points to draw the line
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\n" ); document.write( " So lets plug in some points
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\n" ); document.write( " Plug in x=-7
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\n" ); document.write( " \"y=1%2A%28-7%29-2\"
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\n" ); document.write( " \"y=-7-2\" Multiply
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\n" ); document.write( " \"y=-9\" Add
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\n" ); document.write( " So here's one point (-7,-9)
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\n" ); document.write( " Now lets find another point
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\n" ); document.write( " Plug in x=-6
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\n" ); document.write( " \"y=1%2A%28-6%29-2\"
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\n" ); document.write( " \"y=-6-2\" Multiply
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\n" ); document.write( " \"y=-8\" Add
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\n" ); document.write( " So here's another point (-6,-8). Add this to our graph
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\n" ); document.write( " Now draw a line through these points
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\n" ); document.write( " So this is the graph of \"y=1%2Ax-2\" through the points (-7,-9) and (-6,-8)
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\n" ); document.write( " So from the graph we can see that the slope is \"1%2F1\" (which tells us that in order to go from point to point we have to start at one point and go up 1 units and to the right 1 units to get to the next point) the y-intercept is (0,\"-2\")and the x-intercept is (\"2\",0)
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\n" ); document.write( " We could graph this equation another way. Since \"b=-2\" this tells us that the y-intercept (the point where the graph intersects with the y-axis) is (0,\"-2\").
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\n" ); document.write( " So we have one point (0,\"-2\")
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\n" ); document.write( " Now since the slope is \"1%2F1\", this means that in order to go from point to point we can use the slope to do so. So starting at (0,\"-2\"), we can go up 1 units
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\n" ); document.write( " and to the right 1 units to get to our next point
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\n" ); document.write( " Now draw a line through those points to graph \"y=1%2Ax-2\"
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\n" ); document.write( " So this is the graph of \"y=1%2Ax-2\" through the points (0,-2) and (1,-1)
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