document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=924971>Question 924971</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hello, I was wondering if you could help me with this math problem. The question is \"Pure copper was mixed with 34 kg of a 12% copper alloy to produce a new alloy that is 32% copper. How much of the pure copper was used to make the new alloy?\"\r<BR>\n" );
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document.write( "I tried to work the problem out with an equation, but I could not get the correct equation. <BR>\n" );
document.write( "Anything would help. I am so lost. <BR>\n" );
document.write( "Thanks!<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #561267 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=561267\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Sure<BR>\n" );
document.write( "Let x=amount of pure copper needed<BR>\n" );
document.write( "Now we know that the amount of pure copper that exists  before the mixture takes place (x+0.12*34) has to equal the amount of pure copper that exists after the mixture takes place (0.32*(34+x)). Soooo our equation to solve is:<BR>\n" );
document.write( "x+0.12*34=0.32(34+x)<BR>\n" );
document.write( "You solve\r<BR>\n" );
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document.write( "Hope this helps---ptaylor<BR>\n" );
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