document.write( "Question 924982: An airplane takes off at a 15° angle and travels at the rate of 350 ft/sec. Approximately how long does it take the airplane to reach an altitude of 25,000 feet? (Round your answer to two decimal places.)
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Algebra.Com's Answer #561233 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
If you draw out the triangle, you get \r
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\n" ); document.write( "\n" ); document.write( "* y is the height of the airplane at time t (y is the opposite side)\r
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\n" ); document.write( "\n" ); document.write( "* 350t represents how far along the hypotenuse the plane has traveled\r
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\n" ); document.write( "\n" ); document.write( "* t is time in seconds\r
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\n" ); document.write( "\n" ); document.write( "From the drawing above, we see \r
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\n" ); document.write( "\n" ); document.write( "opposite = y\r
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\n" ); document.write( "\n" ); document.write( "hypotenuse = 350t \r
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\n" ); document.write( "\n" ); document.write( "So that means we can say\r
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\n" ); document.write( "\n" ); document.write( "sin(theta) = opposite/hypotenuse\r
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\n" ); document.write( "\n" ); document.write( "sin(15) = y/350t\r
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\n" ); document.write( "\n" ); document.write( "sin(15) = y/350t\r
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\n" ); document.write( "\n" ); document.write( "350t*sin(15) = y\r
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\n" ); document.write( "\n" ); document.write( "(350*sin(15))*t = y\r
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\n" ); document.write( "\n" ); document.write( "y = (350*sin(15))*t\r
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\n" ); document.write( "\n" ); document.write( "The function \"y+=+%28350%2Asin%2815%29%29%2At\" represents how high the plane is at time t.\r
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\n" ); document.write( "\n" ); document.write( "y is the vertical distance.
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\n" ); document.write( "\n" ); document.write( "Plug in y = 25,000 and solve for t\r
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\n" ); document.write( "\n" ); document.write( "\"y+=+%28350%2Asin%2815%29%29%2At\"\r
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\n" ); document.write( "\n" ); document.write( "\"25000+=+%28350%2Asin%2815%29%29%2At\"\r
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\n" ); document.write( "\n" ); document.write( "\"25000%2F%28350%2Asin%2815%29%29+=+t\"\r
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\n" ); document.write( "\n" ); document.write( "\"t+=+25000%2F%28350%2Asin%2815%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"t+=+275.978807511162\" ... use a calculator here (type in \"25000/(350*sin(15))\" without quotes). \r
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\n" ); document.write( "\n" ); document.write( "Special Note: make sure you're in degree mode and NOT in radian mode.\r
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\n" ); document.write( "\n" ); document.write( "\"t+=+275.98\" ... round to 2 decimal places\r
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\n" ); document.write( "\n" ); document.write( "It takes approximately 275.98 seconds for the airplane to climb to 25,000 ft. So that is your answer.\r
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\n" ); document.write( "\n" ); document.write( "Note: 275.98 seconds = 4 minutes, 35.98 seconds = 4.6 minutes (approximate). This is extra info to possibly think of the timeframe in an easier context.
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