document.write( "Question 78248: Solve this equation by completing the square:\r
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Algebra.Com's Answer #56118 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"-4x%5E2+%2B+8x=7\"
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Solved by pluggable solver: Completing the Square to Get a Quadratic into Vertex Form

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\n" ); document.write( " \"y=-4+x%5E2%2B8+x-7\" Start with the given equation
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\n" ); document.write( " \"y%2B7=-4+x%5E2%2B8+x\" Add \"7\" to both sides
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\n" ); document.write( " \"y%2B7=-4%28x%5E2-2x%29\" Factor out the leading coefficient \"-4\"
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\n" ); document.write( " Take half of the x coefficient \"-2\" to get \"-1\" (ie \"%281%2F2%29%28-2%29=-1\").
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\n" ); document.write( " Now square \"-1\" to get \"1\" (ie \"%28-1%29%5E2=%28-1%29%28-1%29=1\")
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\n" ); document.write( " \"y%2B7=-4%28x%5E2-2x%2B1-1%29\" Now add and subtract this value inside the parenthesis. Doing both the addition and subtraction of \"1\" does not change the equation
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\n" ); document.write( " \"y%2B7=-4%28%28x-1%29%5E2-1%29\" Now factor \"x%5E2-2x%2B1\" to get \"%28x-1%29%5E2\"
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\n" ); document.write( " \"y%2B7=-4%28x-1%29%5E2%2B4%281%29\" Distribute
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\n" ); document.write( " \"y%2B7=-4%28x-1%29%5E2%2B4\" Multiply
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\n" ); document.write( " \"y=-4%28x-1%29%5E2%2B4-7\" Now add \"%2B7\" to both sides to isolate y
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\n" ); document.write( " \"y=-4%28x-1%29%5E2-3\" Combine like terms
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\n" ); document.write( " Now the quadratic is in vertex form \"y=a%28x-h%29%5E2%2Bk\" where \"a=-4\", \"h=1\", and \"k=-3\". Remember (h,k) is the vertex and \"a\" is the stretch/compression factor.
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\n" ); document.write( " Check:
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\n" ); document.write( " Notice if we graph the original equation \"y=-4x%5E2%2B8x-7\" we get:
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\n" ); document.write( " \"graph%28500%2C500%2C-10%2C10%2C-10%2C10%2C-4x%5E2%2B8x-7%29\" Graph of \"y=-4x%5E2%2B8x-7\". Notice how the vertex is (\"1\",\"-3\").
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\n" ); document.write( " Notice if we graph the final equation \"y=-4%28x-1%29%5E2-3\" we get:
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\n" ); document.write( " \"graph%28500%2C500%2C-10%2C10%2C-10%2C10%2C-4%28x-1%29%5E2-3%29\" Graph of \"y=-4%28x-1%29%5E2-3\". Notice how the vertex is also (\"1\",\"-3\").
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\n" ); document.write( " So if these two equations were graphed on the same coordinate plane, one would overlap another perfectly. So this visually verifies our answer.
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\n" ); document.write( "\n" ); document.write( "So now we have\r
\n" ); document.write( "\n" ); document.write( "\"-4%28x-1%29%5E2-3=0\"
\n" ); document.write( "\"-4%28x-1%29%5E2=3\" Add 3 to both sides
\n" ); document.write( "\"%28x-1%29%5E2=3%2F-4\" Divide both sides by -4
\n" ); document.write( "\"x-1=0%2B-sqrt%28-3%2F4%29\" Take the square root of both sides
\n" ); document.write( "\"x=0%2B-sqrt%28-3%2F4%29%2B1\" Add 1 to both sides\r
\n" ); document.write( "\n" ); document.write( "Since we cannot take the square root of a negative number, we must factor out a negative 1\r
\n" ); document.write( "\n" ); document.write( "\"x=0%2B-sqrt%28-1%29sqrt%283%2F4%29%2B1\" \r
\n" ); document.write( "\n" ); document.write( "Now we'll let \"i=sqrt%28-1%29\" and say\r
\n" ); document.write( "\n" ); document.write( "\"x=0%2B-sqrt%283%2F4%29i%2B1\"\r
\n" ); document.write( "\n" ); document.write( "\"x=0%2B-sqrt%283%29%2F2%2Ai%2B1\" Reduce the denominator\r
\n" ); document.write( "\n" ); document.write( "So our answer is \r
\n" ); document.write( "\n" ); document.write( "\"x=sqrt%283%29%2F2%2Ai%2B1\" or \"x=-sqrt%283%29%2F2%2Ai%2B1\"
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