Algebra.Com's Answer #56118 by jim_thompson5910(35256)  You can put this solution on YOUR website!  \n" );
document.write( " Subtract 7 from both sides\r \n" );
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document.write( " Solved by pluggable solver: Completing the Square to Get a Quadratic into Vertex Form | \n" );
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document.write( " Start with the given equation \n" );
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document.write( " Add to both sides \n" );
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document.write( " Factor out the leading coefficient  \n" );
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document.write( " Take half of the x coefficient to get (ie ). \n" );
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document.write( " Now square to get (ie ) \n" );
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document.write( " Now add and subtract this value inside the parenthesis. Doing both the addition and subtraction of does not change the equation \n" );
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document.write( " Now factor to get  \n" );
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document.write( " Distribute \n" );
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document.write( " Multiply \n" );
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document.write( " Now add to both sides to isolate y \n" );
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document.write( " Combine like terms \n" );
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document.write( " Now the quadratic is in vertex form where , , and . Remember (h,k) is the vertex and \"a\" is the stretch/compression factor. \n" );
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document.write( " Check: \n" );
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document.write( " Notice if we graph the original equation we get: \n" );
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document.write( " Graph of . Notice how the vertex is ( , ). \n" );
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document.write( " Notice if we graph the final equation we get: \n" );
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document.write( " Graph of . Notice how the vertex is also ( , ). \n" );
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document.write( " So if these two equations were graphed on the same coordinate plane, one would overlap another perfectly. So this visually verifies our answer. \n" );
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document.write( "So now we have\r \n" );
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document.write( " Add 3 to both sides \n" );
document.write( " Divide both sides by -4 \n" );
document.write( " Take the square root of both sides \n" );
document.write( " Add 1 to both sides\r \n" );
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document.write( "Since we cannot take the square root of a negative number, we must factor out a negative 1\r \n" );
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document.write( "Now we'll let and say\r \n" );
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document.write( " Reduce the denominator\r \n" );
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document.write( "So our answer is \r \n" );
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document.write( " or \n" );
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