document.write( "Question 924911: Find the center (h,k) and radius r of the circle with the given equation.
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document.write( "4x^2+4y^2-12x+16y-5=0\r
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document.write( "Can you please break it down in simple steps? \n" );
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Algebra.Com's Answer #561166 by ewatrrr(24785)![]() ![]() You can put this solution on YOUR website! Re TY \n" ); document.write( "the 5/4 came in two steps... see below (Generally these types do not involve a fraction) \n" ); document.write( "4x^2+4y^2-12x+16y-5=0 \n" ); document.write( "4x^2 - 12x +4y^2 + 16y = 5 ****added 5 to both sides of the EQ \n" ); document.write( "x^2 - 3x + y^2 + 4y = 5/4 ****divided thru by 4 \n" ); document.write( "....... \n" ); document.write( "x^2 - 3x + (3/2)^2 + y^2 + 4y + 4 = 5/4 + (3/2)^2 + 4 \n" ); document.write( "(x- 3/2)^2 + (y+2)^2 = 5/4 + 9/4 + 16/4 \n" ); document.write( "......... \n" ); document.write( "(x- 3/2)^2 + (y+2)^2 = 30/4\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |