document.write( "Question 78224: Russ and Janet are running in the Apple Hill Fun Run. Russ runs at 7 mph, Janet at 5 mph. If they start at the same time, how long will it be before the are 1/2 mile apart?\r
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document.write( "The answer should be 15 min, but I'm not sure how to solve this...\r
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document.write( "Thank you for your help. \n" );
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Algebra.Com's Answer #56113 by Edwin McCravy(20060)![]() ![]() You can put this solution on YOUR website! \r\n" ); document.write( "Russ and Janet are running in the Apple Hill Fun Run.\r\n" ); document.write( "\r\n" ); document.write( " Want to know what that is? \r\n" ); document.write( " It happens every fall in Sacremento CA\r\n" ); document.write( " http://www.applehillrun.org/race_info.html\r\n" ); document.write( "\r\n" ); document.write( "Russ runs at 7 mph, Janet at 5 mph. If they start at the\r\n" ); document.write( "same time, how long will it be before the are 1/2 mile apart?\r\n" ); document.write( "\r\n" ); document.write( "You can do it in your head. They are separating at the rate \r\n" ); document.write( "of 7-5 or 2 mph. So in an hour they would be 2 miles apart, \r\n" ); document.write( "so in 15 minutes they will be half a mile apart. \r\n" ); document.write( "Answer: 15 minutes.\r\n" ); document.write( "\r\n" ); document.write( "But your teacher probably won't accept that way of doing it. \r\n" ); document.write( "To make your teacher happy, make this DRT chart\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( " DISTANCE RATE TIME\r\n" ); document.write( "Russ \r\n" ); document.write( "Janet \r\n" ); document.write( "\r\n" ); document.write( "Let the time it takes them be t. So fill in\r\n" ); document.write( "t for both their times.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( " DISTANCE RATE TIME\r\n" ); document.write( "Rus t\r\n" ); document.write( "Janet t\r\n" ); document.write( "\r\n" ); document.write( "Now fill in their rates, 7 and 5\r\n" ); document.write( "\r\n" ); document.write( " DISTANCE RATE TIME\r\n" ); document.write( "Rus 7 t\r\n" ); document.write( "Janet 5 t\r\n" ); document.write( "\r\n" ); document.write( "Now use DISTANCE = RATE × TIME to\r\n" ); document.write( "fill in the distances:\r\n" ); document.write( "\r\n" ); document.write( " DISTANCE RATE TIME\r\n" ); document.write( "Rus 7t 7 t\r\n" ); document.write( "Janet 5t 5 t\r\n" ); document.write( "\r\n" ); document.write( "Now we want to find the time when\r\n" ); document.write( "their distances apart are 1/2 mile\r\n" ); document.write( "\r\n" ); document.write( "Russ' distance MINUS Janet's distance = 1/2 mile\r\n" ); document.write( "\r\n" ); document.write( " 7t - 5t = 1/2\r\n" ); document.write( "\r\n" ); document.write( " 2t = 1/2\r\n" ); document.write( "\r\n" ); document.write( "Multiply both sides by 2 to clear of fractions:\r\n" ); document.write( "\r\n" ); document.write( " 4t = 1\r\n" ); document.write( "\r\n" ); document.write( " t = 1/4 hour\r\n" ); document.write( "\r\n" ); document.write( "and 1/4 an hour equals 15 minutes.\r\n" ); document.write( "\r\n" ); document.write( "Edwin \n" ); document.write( " \n" ); document.write( " |