document.write( "Question 924709: Determine algebraically the solution set to the following quadratic-quadratic system of equations.
\n" ); document.write( "Y=-2x^2-3x+3
\n" ); document.write( "Y=-x^2-x+7/4
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Algebra.Com's Answer #561079 by Fombitz(32388)\"\" \"About 
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Set them equal to each other and solve for \"x\".
\n" ); document.write( "\"-2x%5E2-3x%2B3=-x%5E2-x%2B7%2F4\"
\n" ); document.write( "\"-x%5E2-2x%2B5%2F4=0\"
\n" ); document.write( "\"4x%5E2%2B8x-5=0\"
\n" ); document.write( "\"%282x-1%29%282x%2B5%29=0\"
\n" ); document.write( "Two solutions:
\n" ); document.write( "\"2x-1=0\"
\n" ); document.write( "\"2x=1\"
\n" ); document.write( "\"x=1%2F2\"
\n" ); document.write( "and
\n" ); document.write( "\"2x%2B5=0\"
\n" ); document.write( "\"2x=-5\"
\n" ); document.write( "\"x=-5%2F2\"
\n" ); document.write( "Now that you have the x-coordinates, plug into either equation to find the matching y-coordinates.
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