document.write( "Question 924768: The are of a rectangle is 400cm^2. If the length of one of its sides is \"x\"cm, express the length of the other side and hence the perimeter in terms of X. Find the value of X which makes the perimeter a minimum. \n" ); document.write( "
Algebra.Com's Answer #561074 by josgarithmetic(39618)![]() ![]() ![]() You can put this solution on YOUR website! ...perimeter a minimum? \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "If \"one of the sides\" is x, then the other side is y. LOWER-CASE x; switching case level is incorrect unless you have a specific reason for using both case levels.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "You want to know for what value of x will p be the minimum.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "This seems not to help. Going back to the red-outlined formula for p, the use of derivative should be useful, since I cannot right now think of a less advanced way.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Max or Min? \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Is this x for a maximum or a minimum? \n" ); document.write( "Letting the technology show us, \n" ); document.write( " \n" ); document.write( "Indicates that perimeter has a minumum. The value there for the min perimeter should be |