document.write( "Question 924768: The are of a rectangle is 400cm^2. If the length of one of its sides is \"x\"cm, express the length of the other side and hence the perimeter in terms of X. Find the value of X which makes the perimeter a minimum. \n" ); document.write( "
Algebra.Com's Answer #561074 by josgarithmetic(39618)\"\" \"About 
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...perimeter a minimum?
\n" ); document.write( "\"2x%2B2y=p\";
\n" ); document.write( "\"xy=400\"
\n" ); document.write( "If \"one of the sides\" is x, then the other side is y. LOWER-CASE x; switching case level is incorrect unless you have a specific reason for using both case levels.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"y=400%2Fx\";
\n" ); document.write( "\"2%28400%2Fx%29%2B2x=p\"
\n" ); document.write( "\"highlight%28p=800%2Fx%2B2x%29\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "You want to know for what value of x will p be the minimum.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"p=800%2Fx%2B2x%2Ax%2Fx\"
\n" ); document.write( "\"p=%28800%2B2x%5E2%29%2Fx\"
\n" ); document.write( "This seems not to help. Going back to the red-outlined formula for p, the use of derivative should be useful, since I cannot right now think of a less advanced way.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"dp%2Fdx=%28-1%29800x%5E%28-2%29%2B2\"
\n" ); document.write( "\"dp%2Fdx=2-800%2Fx%5E2\"
\n" ); document.write( "Max or Min?
\n" ); document.write( "\"highlight_green%282-800%2Fx%5E2=0%29\"
\n" ); document.write( "\"2=800%2Fx%5E2\"
\n" ); document.write( "\"2%2Ax%5E2=800\"
\n" ); document.write( "\"x%5E2=400\"
\n" ); document.write( "\"highlight%28x=20%29\"\r
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\n" ); document.write( "\n" ); document.write( "Is this x for a maximum or a minimum?
\n" ); document.write( "Letting the technology show us,
\n" ); document.write( "\"graph%28300%2C300%2C-4%2C35%2C-4%2C450%2C800%2Fx%2B2x%29\"
\n" ); document.write( "Indicates that perimeter has a minumum. The value there for the min perimeter should be \"p=800%2F20%2B2%2A20\", \"p=40%2B40=highlight%2880%29\".
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