document.write( "Question 78204: An artist wants her painting to be in the shape of a golden rectangle. If the length of the painting is 36 inches, then what should be the width? \n" ); document.write( "
Algebra.Com's Answer #56104 by stanbon(75887)\"\" \"About 
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An artist wants her painting to be in the shape of a golden rectangle. If the length of the painting is 36 inches, then what should be the width?
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\n" ); document.write( "If a rectangle has length a and width b and the larger demention is \"a\",
\n" ); document.write( "the golden ratio is (a+b)/a =a/b
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\n" ); document.write( "Then larger/smaller = (1+sqrt5)2 = 1.6180339887...
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\n" ); document.write( "Your problem:
\n" ); document.write( "If 36 is the larger dimension for the picture you get:
\n" ); document.write( "36/smaller = 1.6180.../1
\n" ); document.write( "smaller = 36/1.6180=22.249...
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\n" ); document.write( "If 36 is the smaller dimension for the picture you get:
\n" ); document.write( "larger/36 = 1.6180
\n" ); document.write( "larger = 1.6180,,,*36 = 58.24922....
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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