document.write( "Question 924701: Thirty-five small communities in Connecticut (population near 10,000 each) gave an average of x = 138.5 reported cases of larceny per year. Assume that σ is known to be 44.5 cases per year.
\n" ); document.write( "(a) Find a 90% confidence interval for the population mean annual number of reported larceny cases in such communities. What is the margin of error? (Round your answers to one decimal place.)
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\n" ); document.write( "\n" ); document.write( "(b) Find a 95% confidence interval for the population mean annual number of reported larceny cases in such communities. What is the margin of error? (Round your answers to one decimal place.)
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\n" ); document.write( "\n" ); document.write( "(c) Find a 99% confidence interval for the population mean annual number of reported larceny cases in such communities. What is the margin of error? (Round your answers to one decimal place.)
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Algebra.Com's Answer #561035 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
Thirty-five small communities in Connecticut (population near 10,000 each) gave an average of x = 138.5 reported cases of larceny per year. Assume that σ is known to be 44.5 cases per year.
\n" ); document.write( " (a) Find a 90% confidence interval for the population mean annual number of reported larceny cases in such communities. What is the margin of error? (Round your answers to one decimal place.)
\n" ); document.write( "x-bar = 138.5
\n" ); document.write( "ME = 1.645*44.5/sqrt(35) = 12.38
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\n" ); document.write( " lower limit = 138.5-12.38 = 126.1
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\n" ); document.write( " upper limit = 138.5+12.38 = 150.0
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\n" ); document.write( "(b) Find a 95% confidence interval for the population mean annual number of reported larceny cases in such communities. What is the margin of error? (Round your answers to one decimal place.)
\n" ); document.write( " lower limit:: 138.5-1.96*44.5/sqrt(35) = 123.8
\n" ); document.write( "upper limit:: 138.5+1.96*44.5/sqrt(35) = 153.2
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\n" ); document.write( "(c) Find a 99% confidence interval for the population mean annual number of reported larceny cases in such communities. What is the margin of error? (Round your answers to one decimal place.)
\n" ); document.write( "Comment:: Change the \"z\" value to 2.5758 and do the arithmetic
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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