document.write( "Question 924549: How do you find an exterior angle when all you know is ABC + BCA + CAB = 180 5x + 8 + 6x + 22 + 3x - 25 = 180 14x =175 x = 12.5 M\n" ); document.write( "
Algebra.Com's Answer #561009 by MathLover1(20855)\"\" \"About 
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you know is \"ABC+%2B+BCA+%2B+CAB+=+180\"\r
\n" ); document.write( "\n" ); document.write( "you also know it's a triangle\r
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\n" ); document.write( "\n" ); document.write( "you know \"5x+%2B+8+%2B+6x+%2B+22+%2B+3x+-+25+=+180\"
\n" ); document.write( "\"14x+=175\"
\n" ); document.write( "\"x+=+12.5\"\r
\n" ); document.write( "\n" ); document.write( "measure of each angle is:\r
\n" ); document.write( "\n" ); document.write( " M< \"BAC+=+5X%2B8+=+70.5\"
\n" ); document.write( " M< \"ABC=6X%2B22+=+97\"
\n" ); document.write( "M< \"BCA=3X-25+=+12.5\"\r
\n" ); document.write( "\n" ); document.write( "you also know that an measure of an exterior angle of a triangle is equal to the sum of the measures of the two non-adjacent interior angles \r
\n" ); document.write( "\n" ); document.write( "let's exterior angles be \"A\", \"B\", and \"C\" (the letter of each vertex)\r
\n" ); document.write( "\n" ); document.write( "then \r
\n" ); document.write( "\n" ); document.write( "M< \"A\"=M< \"ABC%2BBCA\"=>M< \"97%2B12.5\"=>M< \"109.5\"\r
\n" ); document.write( "\n" ); document.write( "M< \"B\"=M< \"BAC%2BBCA\"=>M< \"70.5%2B12.5\"=>M< \"83\"\r
\n" ); document.write( "\n" ); document.write( "M< \"C\"=M< \"BAC%2BABC\"=>M< \"70.5%2B97\"=>M< \"167.5\"\r
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\n" ); document.write( "\n" ); document.write( "or, solve it using the sum of an exterior angle and its corresponding interior angle which is \"180\"\r
\n" ); document.write( "\n" ); document.write( " exterior angle \"A\" and \"BAC\" sum up to \"180\"\r
\n" ); document.write( "\n" ); document.write( "so, \r
\n" ); document.write( "\n" ); document.write( "\"A=180-BAC=180-70.5=109.5\"\r
\n" ); document.write( "\n" ); document.write( "\"B=180-ABC=180-97=83\"\r
\n" ); document.write( "\n" ); document.write( "\"C=180-BCA=180-12.5=167.5\"
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