document.write( "Question 924488: The average monthly cellular bill is $73. Suppose local monthly household call phone bills are normally distributed with a standard deviation of $11.35.\r
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document.write( "a. What is the probability that a randomly selected monthly cell bill is less than $100
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document.write( "b. what is the probability that a randomly selected monthly cell bill is between $70 and $90. \n" );
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Algebra.Com's Answer #560886 by ewatrrr(24785)![]() ![]() You can put this solution on YOUR website! mean = 73, sd = 11.35, \n" ); document.write( "Using the z-value to determine the Probability: \n" ); document.write( ".... \n" ); document.write( "And...Using a TI calculator 0r similarly a Casio fx-115 ES plus \n" ); document.write( "P( x < 100) = P( z < 27/11.35) = P( z < 2.3788) = normalcdf(-100, 2.3788) = .9913 \n" ); document.write( "...... \n" ); document.write( "For the normal distribution: Below: z = 0, z = ± 1, z= ±2 , z= ±3 are plotted. \n" ); document.write( "Area under the standard normal curve to the left of the particular z is P(z < than its value) \n" ); document.write( "Note: z = 0 (x value: the mean) 50% of the area under the curve is to the left and 50% to the right \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |