document.write( "Question 924438: The perimeter of a regular lawn is 60m and its diagonal is 25m. If the length of the lawn is m, show that
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document.write( "How to solve this question? Thanks. \n" );
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Algebra.Com's Answer #560850 by Cromlix(4381)![]() ![]() You can put this solution on YOUR website! Perimeter = 2 x Length + 2 x width \n" ); document.write( "Length = x \n" ); document.write( "Width = y \n" ); document.write( "Perimeter = 2x + 2y \n" ); document.write( "2x + 2y = 60 \n" ); document.write( "2y = 60 - 2x \n" ); document.write( "2y = 2(30 - x) \n" ); document.write( "Divide both sides by 2 \n" ); document.write( "y = 30 - x\r \n" ); document.write( "\n" ); document.write( "Using the diagonal. \n" ); document.write( "x^2 + y^2 = 25^2 (Pythagoras theorem) \n" ); document.write( "Substitute y = 30 - x \n" ); document.write( "x^2 + (30 - x)^2 = 625 \n" ); document.write( "Multiply out bracket \n" ); document.write( "x^2 + 900 - 60 x + x^2 = 625 \n" ); document.write( "Collect like terms \n" ); document.write( "2x^2 - 60x + 900 - 625 = 0 \n" ); document.write( "2x^2 - 60x + 275 = 0 \n" ); document.write( "Your answer.\r \n" ); document.write( "\n" ); document.write( "Hope this helps. \n" ); document.write( ":-) \n" ); document.write( " |