document.write( "Question 924358: if x + 4/y = 4 and y + 6/x = 6, then find (x,y) \n" ); document.write( "
Algebra.Com's Answer #560826 by ptaylor(2198)![]() ![]() You can put this solution on YOUR website! x+4/y=4 multiply each term by y \n" ); document.write( "xy+4=4y-----eq1 \n" ); document.write( "y+6/x=6 multiply each term by x \n" ); document.write( "xy+6=6x---eq2\r \n" ); document.write( "\n" ); document.write( "Rearranging eq1, we get: \n" ); document.write( "4y-xy=4 or \n" ); document.write( "y(4-x)=4 \n" ); document.write( "y=4/(4-x)----eq1a--- substitute this into eq2: \n" ); document.write( "(4x/(4-x))+6=6x multiply each term by (4-x) \n" ); document.write( "4x+6(4-x)=6x(4-x) \n" ); document.write( "4x+24-6x=24x-6x^2 collecting like terms and rearranging, we get: \n" ); document.write( "6x^2-26x+24=0 divide by 6 \n" ); document.write( "x^2-(13/3)x+4=0 a quadratic in standard form and it can be factored \n" ); document.write( "(x-3)(x-4/3)=0 \n" ); document.write( "Sooooo \n" ); document.write( "x=3 and \n" ); document.write( "x=4/3 \n" ); document.write( "substitute each of these values into eq1a and solve for y: \n" ); document.write( "y=4/(4-3) or y=4 \n" ); document.write( "y=4/(4-4/3)=4/((12-4)/3)=12/8=3/2 \n" ); document.write( "So when x=3, y=4 \n" ); document.write( "when x=4/3, y=3/2 \n" ); document.write( "CK \n" ); document.write( "when x=3, y=4 substitute into eq1 \n" ); document.write( "12+4=4*4 \n" ); document.write( "16=16 \n" ); document.write( "when x=4/3, y=3/2 \n" ); document.write( "substitute into eq1 \n" ); document.write( "(4/3)(3/2)+4=4(3/2) \n" ); document.write( "2+4=12/2=6 \n" ); document.write( "6=6\r \n" ); document.write( "\n" ); document.write( "Hope this helps----ptaylor\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |