document.write( "Question 924409: A group of 12 people need to form a line. The line will consist of exactly 9 of the people. Person X and Person Y have to be either third or fourth in line. How many different orders are possible? \n" ); document.write( "
Algebra.Com's Answer #560806 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
what i think is:\r
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\n" ); document.write( "\n" ); document.write( "if x and y have to occupy the third and fourth slot, that leaves 7 slots for the other 10 people.\r
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\n" ); document.write( "\n" ); document.write( "instead of 12P9, you get 10P7 * 2P2\r
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\n" ); document.write( "\n" ); document.write( "10P7 = 10*9*8*7*6*5*4 = 603800\r
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\n" ); document.write( "\n" ); document.write( "2P2 = 2*1 = 2\r
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\n" ); document.write( "\n" ); document.write( "10P7 * 2P2 = 603800 * 2 = 1209600\r
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\n" ); document.write( "\n" ); document.write( "the 10P7 takes care of the number of arrangements for the 10 remaining people in 7 remaining slots.\r
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\n" ); document.write( "\n" ); document.write( "the 2P1 takes care of the number of arrangements for the 2 people in 2 slots.\r
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\n" ); document.write( "\n" ); document.write( "to see this with smaller numbers, consider 6 people for 4 slots where x and y have to be in position 1 and 2.\r
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\n" ); document.write( "\n" ); document.write( "instead of 6P4 = 360 possible arrangements, you have 2P2 * 4P2 = 24 possible arrangements.\r
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\n" ); document.write( "\n" ); document.write( "let the people be xy1234\r
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\n" ); document.write( "\n" ); document.write( "x is a person, y is a person, 1 is a person, 2 is a person, etc.\r
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\n" ); document.write( "\n" ); document.write( "x and y have to be in positions 1 and 2, so those positions are filled.\r
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\n" ); document.write( "\n" ); document.write( "the possible positions are:\r
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\n" ); document.write( "\n" ); document.write( "xy12
\n" ); document.write( "xy13
\n" ); document.write( "xy14
\n" ); document.write( "xy23
\n" ); document.write( "xy24
\n" ); document.write( "xy34\r
\n" ); document.write( "\n" ); document.write( "yx12
\n" ); document.write( "yx13
\n" ); document.write( "yx14
\n" ); document.write( "yx23
\n" ); document.write( "yx24
\n" ); document.write( "yx34\r
\n" ); document.write( "\n" ); document.write( "xy21
\n" ); document.write( "xy31
\n" ); document.write( "xy41
\n" ); document.write( "xy32
\n" ); document.write( "xy42
\n" ); document.write( "xy43\r
\n" ); document.write( "\n" ); document.write( "yx21
\n" ); document.write( "yx31
\n" ); document.write( "yx41
\n" ); document.write( "yx32
\n" ); document.write( "yx42
\n" ); document.write( "yx43\r
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\n" ); document.write( "\n" ); document.write( "that's a total of 24.\r
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\n" ); document.write( "\n" ); document.write( "the formula appears to work so it can be applied to the larger problem.\r
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\n" ); document.write( "\n" ); document.write( "the solution appears to be:\r
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\n" ); document.write( "\n" ); document.write( "10P7 * 2P2 = 1209600\r
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\n" ); document.write( "\n" ); document.write( "x and y have to be in positions 2 and 3
\n" ); document.write( "that leaves only 1 position for a and b and c\r
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\n" ); document.write( "\n" ); document.write( "the possible arrangements are:\r
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\n" ); document.write( "\n" ); document.write( "axy
\n" ); document.write( "bxy
\n" ); document.write( "cxy
\n" ); document.write( "ayx
\n" ); document.write( "byx
\n" ); document.write( "cyx\r
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\n" ); document.write( "\n" ); document.write( "there are no other possible arrangements.\r
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