document.write( "Question 924350: A passenger train traveled 110 miles in the same amount of time it took a freight train to travel 90 miles. The rate of the freight train was 10 miles per hour slower than the rate of the passenger train. Find the rate of the passenger train. \n" ); document.write( "

Algebra.Com's Answer #560784 by MathTherapy(10553) $\"\"$ $\"About$

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A passenger train traveled 110 miles in the same amount of time it took a freight train to travel 90 miles. The rate of the freight train was 10 miles per hour slower than the rate of the passenger train. Find the rate of the passenger train.
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document.write( "Let passenger train's speed be S
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document.write( "Then freight train's speed = S - 10
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document.write( "Therefore, 
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document.write( "110(S - 10) = 90S ------ Cross-multiplying
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document.write( "110S - 1,100 = 90S
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document.write( "110S - 90S = 1,100
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document.write( "20S = 1,100
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document.write( "S, or passenger train's speed = , or  mph \n" );
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