document.write( "Question 924356: Scott’s boat has a top speed of 6 miles per hour in still water. While traveling on a river at top speed, he went 10 miles upstream in the same amount of time he went 30 miles downstream. Find the rate of the river current. \n" ); document.write( "
Algebra.Com's Answer #560782 by TimothyLamb(4379)\"\" \"About 
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x = boat speed = 6 mph
\n" ); document.write( "y = current speed
\n" ); document.write( "---
\n" ); document.write( "s = d/t
\n" ); document.write( "---
\n" ); document.write( "up:
\n" ); document.write( "x - y = 10/t
\n" ); document.write( "---
\n" ); document.write( "down:
\n" ); document.write( "x + y = 30/t
\n" ); document.write( "---
\n" ); document.write( "x - y = 10/t
\n" ); document.write( "y = x - 10/t
\n" ); document.write( "---
\n" ); document.write( "x + y = 30/t
\n" ); document.write( "y = 30/t - x
\n" ); document.write( "---
\n" ); document.write( "y = x - 10/t
\n" ); document.write( "y = 30/t - x
\n" ); document.write( "x - 10/t = 30/t - x
\n" ); document.write( "2x = 40/t
\n" ); document.write( "x = 20/t
\n" ); document.write( "6 = 20/t
\n" ); document.write( "t = 20/6
\n" ); document.write( "t = 10/3
\n" ); document.write( "---
\n" ); document.write( "answer:
\n" ); document.write( "y = x - 10/t
\n" ); document.write( "y = 6 - 10/(10/3)
\n" ); document.write( "y = 6 - 3
\n" ); document.write( "y = current speed = 3 mph
\n" ); document.write( "---
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