document.write( "Question 78171: A plane flies 720 mi against a steady 30 mi/h headwind and then returns to the same point with the wind. If the entire trip takes 10 hours, what is the plane's speed still in the air? \n" ); document.write( "
Algebra.Com's Answer #56078 by scott8148(6628)\"\" \"About 
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let s=speed in still air ... (rate)*(time)=distance so t=d/r ... (time out)+(time back)=(total time)\r
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\n" ); document.write( "\n" ); document.write( "(720/(s-30))+(720/(s+30))=10 ... multiplying by \"s%5E2-900\" and dividing by 10 gives \"72%28s%2B30%29%2B72%28s-30%29=s%5E2-900\"\r
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\n" ); document.write( "\n" ); document.write( "distributing and rearranging terms gives \"s%5E2-144s-900=0\" ... factoring gives (s-150)(s+6)=0 ... so s=150 mi/h
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