document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=924359>Question 924359</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve the nonlinear system by substitution <BR>\n" );
document.write( "{y=x^2-6x+9 <BR>\n" );
document.write( "{y=-2x+5 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #560779 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39617)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=560779\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The obvious substitution to make is for y as defined with the second equation.  Substitute the expression into the quadratic, first equation; simplify and solve for x.\r<BR>\n" );
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document.write( "Another way to view the system is that you have two equal expressions for y.\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=-2x%2B5=x%5E2-6x%2B9 ALIGN=MIDDLE  ALT=\"-2x%2B5=x%5E2-6x%2B9\"   DISABLED_style= \"max-width:90%; height:auto;\" >.<BR>\n" );
document.write( "Solve that and continue. </SPAN>\n" );
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