document.write( "Question 924297: 3/3y+6 = 2/10-2y \n" ); document.write( "
Algebra.Com's Answer #560763 by srinivas.g(540) You can put this solution on YOUR website! \n" ); document.write( "move (10-2y) to the left and (3y+6) to the right \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " move -6y to the right \n" ); document.write( " 30= 6y+6y+12 \n" ); document.write( " 30= 12y+12 \n" ); document.write( " move 12 to the left \n" ); document.write( " 30-12 = 12y \n" ); document.write( " 18 = 12y \n" ); document.write( " divide with 12 on both sides \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " y= 3/2\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |