document.write( "Question 924217: Can you please help me with this?\r
\n" );
document.write( "\n" );
document.write( "The amount of radioactive material, in grams, present after t days is modeled by:
\n" );
document.write( "A(t)=600e^-0.5t\r
\n" );
document.write( "\n" );
document.write( "a) Find the amount present after 12 days.
\n" );
document.write( "I think I got this one. \r
\n" );
document.write( "\n" );
document.write( "A(12)=600e^-0.5*12
\n" );
document.write( "A(12)=1.487g\r
\n" );
document.write( "\n" );
document.write( "b)find the half-life of the material
\n" );
document.write( "This one I had more trouble with. I got a negative answer when I tried it. \r
\n" );
document.write( "\n" );
document.write( "300=600e^-0.5t
\n" );
document.write( ".5=e^-0.5t
\n" );
document.write( "log base e (.5)=-0.5t
\n" );
document.write( "t=(log base e (.5))/-0.5
\n" );
document.write( "t=-.434yrs\r
\n" );
document.write( "\n" );
document.write( "but that doesn't feel right... \n" );
document.write( "
Algebra.Com's Answer #560692 by MathLover1(20850)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "a) Find the amount present after \n" ); document.write( "I think I got this one. \r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "b)find the half-life of the material \n" ); document.write( " \r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |