document.write( "Question 924196: two times the father's age is 8 more than six times his son's age. ten years ago, the sum of their age was 44. the age of the son is:
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Algebra.Com's Answer #560679 by ewatrrr(24785)\"\" \"About 
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x the son's age and y the Father's age
\n" ); document.write( "(y - 10) + (x-10) = 44
\n" ); document.write( "y = \"-x+%2B+64\"\r
\n" ); document.write( "\n" ); document.write( "2(-x+64) = 6x + 8
\n" ); document.write( "-2x + 128 = 6x + 8
\n" ); document.write( "120 = 8x
\n" ); document.write( "15 = x, the son's age
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\n" ); document.write( "and...checking (Father's age 49)
\n" ); document.write( "2y = 6x + 8
\n" ); document.write( "98 = 90 + 8\r
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