document.write( "Question 924158: If the divisor is
\n" ); document.write( "x+4,
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\n" ); document.write( "2x+3,
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Algebra.Com's Answer #560666 by MathLover1(20850)\"\" \"About 
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\"Dividends\"} and \"divisors\" are the two key ingredients that yield the \"quotient\", or answer, to a division problem. \r
\n" ); document.write( "\n" ); document.write( "The \"dividend\" is the number \"being\" \"divided\", while the \"divisor\" is the number \"by\"\"+which\" the dividend is divided. \r
\n" ); document.write( "\n" ); document.write( "In other words, given \"a%3Ab\" or \"a%2Fb\" , \"a\" is the \"dividend\" and \"b\" is the \"divisor\", and \"q\"\"quotient\"\r
\n" ); document.write( "\n" ); document.write( "so, you are given:\r
\n" ); document.write( "\n" ); document.write( "the divisor is
\n" ); document.write( "\"b=x%2B4\"
\n" ); document.write( "the quotient is
\n" ); document.write( "\"q=2x%2B3\"
\n" ); document.write( "and the remainder is \"5\", \r
\n" ); document.write( "\n" ); document.write( "\"a%2Fb=q\"=>\"a=q%2Ab\" since you have remainder \"5\" you need to add it to the \"q%2Ab\"\r
\n" ); document.write( "\n" ); document.write( "\"a=q%2Ab%2B5\"...substitute \"q\" and \"b\"\r
\n" ); document.write( "\n" ); document.write( "\"a=%282x%2B3%29%2A%28x%2B4%29%2B5\"\r
\n" ); document.write( "\n" ); document.write( "\"a=%282x%5E2%2B8x%2B3x%2B12%29%2B5\"\r
\n" ); document.write( "\n" ); document.write( "\"a=2x%5E2%2B11x%2B17\".......the polynomial being divided\r
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