document.write( "Question 924004: I just want to check if my answer is correct.\r
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document.write( "Problem: The center of the circle is at (-3,-2). If a chord of length 4 is bisected at (3,1), find the length of the radius.\r
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document.write( "My answer is: 3√6 \n" );
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Algebra.Com's Answer #560620 by Theo(13342)![]() ![]() You can put this solution on YOUR website! based on the following, your radius has to be perpendicular to the chord.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "http://www.regentsprep.org/regents/math/geometry/gp14/circlechords.htm\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "so you get a triangle formed by the radius of the circle and the chord such that the ends of the chord that connect to the center of the circle are each a radius of the circle.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the chord is 4 units in length.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "two right triangles are formed with each right triangle having a base of 2 which is 1/2 the length of the chord.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the length of the line segment formed by the radius that bisects the chord is found by taking the 2 points common to that radius and finding the distance between them.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the two points are (-3,-2) and (3,1)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the distance between them will be square root of [(-2-1)^2 + (-3-3)^2] which becomes square root of [9 + 36] which becomes square root of (45).\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "your right triangle has one leg of 2 and one leg of sqrt(45)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "to find the hypotenuse of the right triangle which is the radius of the circle, you need to use the pythagorean formula.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "you will get r^2 = 2^2 + sqrt(45)^2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "that becomes r^2 = 4 + 45 which makes r^2 = 49 which makes r = 7.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the radius of your circle has to be 7.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the equation of your circle becomes:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(x+3)^2 + (y + 2)^2 = 49\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "a graph of the circle and the chord and the radius that bisects the chord is shown below:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " ![]() \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "all the numbers check out.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the radius is 7 \n" ); document.write( "each sice of the chord that is bisected by the radius has a length of 2.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |