document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=924042>Question 924042</A>: <I><SPAN STYLE=\"word-break: break-all;\"> if 3 is subtracted from a number and the remainder is multiplied by 13,the product becomes 91.find the number<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #560573 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=560573\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x - 3 is the remainder when you subtract 3 from x.<BR>\n" );
document.write( "13 * (x-3) = 91<BR>\n" );
document.write( "simplify to get 13x - 39 = 91<BR>\n" );
document.write( "add 39 to both sides of the equation to get 13x = 130<BR>\n" );
document.write( "divide both sides of the eqaution by 13 to get x = 10\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "when x = 10, x-3 = 7<BR>\n" );
document.write( "7 * 13 = 91\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );