document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=924037>Question 924037</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I just want to check if my answer is correct.\r<BR>\n" );
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document.write( "Problem:the center of the circle is at (-3,-2). If a chord of length 4 is bisected at (3,1), find the length of the radius.\r<BR>\n" );
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document.write( "My answer is: &#8730;21 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #560566 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=560566\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let the distance between the two given points be d, r is radius, then we have<BR>\n" );
document.write( "d^2 + 2^2 = r^2<BR>\n" );
document.write( "d = square root( (-3 -3)^2 + (-2 -1)^2 )<BR>\n" );
document.write( "d = square root ( 36 + 9)  and<BR>\n" );
document.write( "d^2 = 45, therefore<BR>\n" );
document.write( "r^2 = 45 + 4 = 49<BR>\n" );
document.write( "r = 7<BR>\n" );
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