document.write( "Question 924053: Assume that SAT scores vary normally with a standard deviation of 100. How many students should be sampled if we want to estimate the population mean SAT at 90% confidence with a margin of error equal to 25? \n" ); document.write( "
Algebra.Com's Answer #560542 by ewatrrr(24785)![]() ![]() You can put this solution on YOUR website! ME = z(sd/sqrt(n)) \n" ); document.write( "n = [z*s/ME]^2 \n" ); document.write( "........... \n" ); document.write( "n = (1.645(100)/25)^2 = 44 (43.2964 to the next whole number) \n" ); document.write( " |